Twice the difference of a number and 2 is added to 6 and the result is 4 more than 3 times the number.

Please check the explanation.

Step-by-step explanation:

Given the statement:

''Twice the difference of a number and 2 is added to 6 and the result is 4 more than 3 times the number''.

Let us break down the statement into an algebraic expression.

First Portion:

Let the number be: n

The difference of a number n and 2: n -2

Twice the difference of a number n and 2: 2(n-2)

Twice the difference of a number and 2 is added to 6 = 2(n-2) + 6

Second Portion:

3 times the number n:  3n

4 more than 3 times the number: 3n + 4

Combine the First portion and Second Portion:

Twice the difference of a number and 2 is added to 6 and the result is 4 more than 3 times the number:

2(n - 2) + 6 = 3n + 4

Therefore, the required algebraic expression is:

BONUS SOLUTION to determine the number n

Let us solve the expression

2(n - 2) + 6 = 3n + 4

2n - 4 + 6 = 3n + 4

flip the equation

3n + 4 = 2n - 4 + 6

3n + 4 = 2n + 2

3n - 2n = 2 - 4

n = -2

Thus, the value of n = -2

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step-by-step explanation: