Three whole numbers are each rounded to the nearest 10 The sum of the three rounded numbers is 80
What is the maximum possible sum of the original three numbers?

9514 1404 393

  92

Step-by-step explanation:

The maximum whole number that will round to 10 is 14, that is, it may be 4 more than the nearest 10.

If all three numbers are 4 more than the nearest 10, their maximum sum will be 12 more than the sum of the rounded numbers.

For example, consider the numbers 34, 34, 24. These have a sum of 92. When rounded to the nearest 10, their values are 30, 30, 20, which have a sum of 80.

The maximum sum of the three original whole numbers is 92.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24