(a) What is wrong with the following equation? x² + x - 42/x-6= x + 7

(x - 6 )(x + 7) + x2 + x - 42
The left-hand side is not defined for x = 0, but the right-hand side is.
The left-hand side is not defined for x = 6, but the right-hand side is.
None of these – the equation is correct.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

-1, -2, -3, -4, -6

step-by-step explanation: