The difference between the compound interest and the simple interest on a certain sum of money for 2 years at 11% per annum is Rs. 363. Find the sum. 1.33,000
2.31,000
3.30,000
4.32,000

★ Given :-Difference between the CI and SI = ₹363Years = 2 yearsRate of interest = 11% pa★ Notations :-p is principalr is the rate of interestt is the time period★ Formula :-Difference between the compound interest and simple interest =p(1+(r/100))^t - p - (p×r×t)/100 = 363★ To find :-Let the sum be :- p★ Solution :-p(1+(r/100))^t - p - (p×r×t)/100 = 363 p( (1+11/100)^2 - 1 - 11×2/100 ) = 363p( (111/100)^2 - 1 - 22/100 ) = 363 p ( 12321 / 10000 - 1 - 22 / 100 ) = 363 p ( (1.2321 - 1.22 ) = 363p ( 0.0121 ) = 363 p = 363 / 0.0121p = 3630000 / 121p = ₹ 30,000

Ans:-The sum is ₹30,000

The answer to your question is b