Given that the area of rectangle IJKL is 500 units? what are its length and width?
1
5x
J
K
8x
1 = 101.5 units, w = 162 4 units
1=35 8 units, w = 23 units
1 = 100 units, w = 62 5 units
1 = 28 units, w = 175 units

d. 17.5 and 28 units

Step-by-step explanation:

An area of a rectangle is length times width. 8x times 5x = 40x^2. 40x^2 is eqaul to 500. After dividing by 40 and taking the square root of the quotient, x is approximately 3.54. 5 times 3.54 and 8 times 3.54 will yield approximately 17.5 and 28 units.

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12