If a triangle has a area of 42 cm^2 and a base of 8 cm, what is the height? show work pl

hb=10.5cm

Step-by-step explanation:

Area of triangle = 1/2(height x base)

The problem states that base is 8 cm greater than the height; therefore, base-8 = height.

A = 1/2(b*h)

42 = 1/2(b*[b-8])

84=(b^2-8b)

rearrange to

b^2 - 8b -84

factor to

(b+8)(b-14)

Therefore, b = -8 cm which makes no sense and

b = +14 cm

and height = 14-8 = 6

Check:

1/2(b*h) = area

1/2(14*6) = 1/2(84)=42

the square root of what number? if you add that, then someone will probably answer the question.

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation: