In the following triangles find A, B and C

small c in triangle ADC equals 110

small b in triangle ADB is 70

small a in triangel ABD equals to 80

small a in triangle PSQ is 119

small b equals in triangel PSR 61

small c in triangel RPS is 79

Step-by-step explanation:

triangle ABC

ADC angel is 60+10=70 ,, 180-70= 110

small c in triangle ADC equals 110

ADB angel is 180-110=70

small b in triangle ADB is 70

ABD angel is 70+30=100 ,, 180-100=80

small a in triangel ABD equals to 80

triangel PQR

PSQ angel is 55+6=61 ,, 180-61=119

small a in triangle PSQ is 119

small a + small b = 180

119+ b = 180

180-119=61

small b equals in triangel PSR 61

RPS angel is 40+61=101 ,, 180-101= 79

small c in triangel RPS is 79

i believe that the answer is

b. y-1=-2(x-4)

hope this !

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130