Just keep getting more homework.
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1. x = 1, y = -3

2. x = 3, y = 4

Step-by-step explanation:

Here, we want to solve the sets of simultaneous equations;

a) -y = 5x-2

-3y = -5x + 14

substitute 1 into ii

3(5x-2) = -5x + 14

15x - 6 = -5x + 14

15x + 5x = 14 + 6

20x = 20

x = 20/20

x = 1

from;

-y = 5x - 2

y = -5x + 2

y = -5(1) + 2

y = -3

b) -2y = -6x + 10

2y = x + 5

Substitute ii into i

-(x + 5) = -6x + 10

-x - 5 = -6x + 10

-x + 6x = 10 + 5

5x = 15

x = 15/5

x = 3

2y = x + 5

2y = 3 + 5

2y = 8

y = 8/2

y = 4

asdsad

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v