Sanjay uses the steps below to solve the equation 4 p + two-fifths (10 + 2 p) = 8. Step 1 Multiply both sides of the equation by Five-halves.
4 p + 10 + 2 p = 20
Step 2 Simplify like terms.
6 p + 10 = 20
Step 3 Subtract 10 on both sides of the equation.
6 p = 10
Step 4 Divide both sides of the equation by 6.
p = StartFraction 10 over 6 EndFraction = Five-thirds = 1 and two-thirds

Which is the first error that Sanjay made when finding the solution?
In step 1, he multiplied by Five-halves instead of by Two-fifths.
In step 1, he did not multiply 4p by Five-halves when multiplying both sides by Five-halves.
In step 3, he should have added 10 to both sides of the equation instead of subtracting 10.
In step 3, he should have divided both sides by 6 instead of subtracting 10

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

1,8,15,22,29,36,43,50

step-by-step explanation:

the answer is a if my teacher taught me correct

there are infinitely many solutions.