The measure of the supplement if an angle is 46 more than 3 times the complement of the angle. Find the angle A. 68 degrees
B. 44 degrees
C. 112 degrees
D. 22 degrees

Let the required angle be x.

⇒3 ×complement of x = 3(90° − x)

According to question;

Supplement of x = 3 × complement of x + 46°

⇒(180° − x) = 3(90° − x) + 46°

⇒180° − x = 270° − 3x + 46°

⇒− x + 3x = 316° − 180°

⇒2x = 136°

⇒x = 68°

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step-by-step explanation:

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3