What is the function of this graph?

x=y^2-2

Step-by-step explanation:

This graph, is a parabola that opens to the right.

To answer this question, we just use the vertex form of a sideways parabola- x=a(y-k)^2+h.

In this case, the vertex is (-2, 0), and our value of a is 1, since it opens to the right.

This gives us: x=1(y-0)^2+(-2)

Which simplifies to: x=y^2-2.

Also, the answer to the previous two questions are wrong.

The D value (Domain) is actually [2, ∞)

The R value (Range) is actually "All real numbers" (-∞, ∞)

Let me know if this helps!