Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation (-7,-6); y = - 4x + 4

y = -4x-34

Step-by-step explanation:

From the line to which the line is parallel, we can get the slope

The general form of a linear model is;

y = mx + b

where m

is the slope and b is the y-intercept

From the question, using the given line,

we have the slope of that line as -4

Now, we want to write the equation of a line that passes through (-7,-6) and has a slope of -4

we can use the point-slope form

for this

That would be;

y-y1 = m(x-x1)

y + 6 = -4(x+ 7)

y + 6 = -4x -28

y = -4x -28-6

y = -4x - 34

answer: answer

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)