You and three friends are going to the fair. The cost for parking is $5 per car and admission to the fair is $19 per person. If you have
a total of $113, how much can each person spend on food?

$17 on food per person

Step-by-step explanation:

The cost of parking a car is $5

Assuming that the friends used one car, then the parking cost=$5

Admission cost is 19

For three people, Admission cost =19*3=57

TOTAl COSTS=Parking cost+Admission cost

TOTAl COSTS=57+5=62

Remaining amount can be used for food

FOOD= 113-62=51

Therefore each person can spend 51/3=$17 on food

I hope this was helpful and clear to follow

$8

Step-by-step explanation:

19 x 4 + 5 + c =113

81 + c =113

-81         -81

c =32

32 divided by 4 ppl = 8

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

x is greater than 5

step-by-step explanation:

2x+7 is greater than 17

    -7                           -7

2x is greater than 10

divide by 2 each side

x is greater than 5