[2] 3
1
> 15.SN
B4
R
A small smooth ring R of weight 8.5N is threaded on a light inextensible string. The ends of the
string are attached to fixed points A and B with A vertically above B. A horizontal force of magnitude
15.5 N acts on R so that the ring is in equilibrium with angle ARB = 90°. The part AR of the string
makes an angle with the horizontal and the part BR makes an angle & with the vertical (see diagram).
The tension in the string is TN. Show that T sin 8 = 12 and T cos 0 = 3.5 and hence find 0.
[6]

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

the answer is 62

ans789

step-by-step explanation:

asdsad

step-by-step explanation: