Aline having a slooe of 3/4 passes through the point (2,-3)

Slope-intercept form:
y=mx+b
m=slope
b=y-intercept

Data:
slope=3/4
(2,-3)  ⇒y₀=-3 when x₀=2

We have to find "b"; therefore:
y=mx+b
-3=(3/4)(2)+b
3/2+b=-3
b=-3-3/2
b=-9/2

y=(3/4)x-9/2

Other method:

Point-slope form; we need a point  (x₀,y₀) and the slope (m).
y-y₀=m(x-x₀)

Data:
m=3/4
(2,-3)

y+3=3/4(x-2)                       Point-slope form
y+3=(3/4)x-3/2
y=(3/4)x-3/2 - 3
y=(3/4)x+(-3-6)/2
y=(3/4)x-9/2

the line will be:    y=(3/4)x-9/2

hope it is correct if not i'm srry i tried to