Which of the following equations have exactly one solution? Choose all answers that apply:
Choose all answers that apply:

(Choice A)
A
-6x-6=-6x-103−6x−6=−6x−103minus, 6, x, minus, 6, equals, minus, 6, x, minus, 103

(Choice B)
B
-6x-6=103x-103−6x−6=103x−103minus, 6, x, minus, 6, equals, 103, x, minus, 103

(Choice C)
C
103x-6=103x-103103x−6=103x−103103, x, minus, 6, equals, 103, x, minus, 103

(Choice D)
D
-103x-6=-6x-103−103x−6=−6x−103

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure