The functions f x) = - I ad g(x) = 2 - 3x The functions f(1) = 31-1. The value of f(2) is
6
3
3
Given that functions fix) = 3x - 1 ad g(x) = 2 - 32, 5(x)=f(x) - g(x). the function (1)
s represented by
a
1
6
bax - 3
3)
Given that functions fix) = 3x -1. The value of a when f(x) = 5 is
6) 2
(c)

∞ this is your sign

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

207/8 is the right

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: