Please help!!
What is the solution set to the inequality 5(x-2)(x + 4) > 0?

x<−4 or x>2

Step-by-step explanation:

Let's solve your inequality step-by-step.

5(x−2)(x+4)>0

5x2+10x−40>0

Let's find the critical points of the inequality.

5x2+10x−40=0

5(x−2)(x+4)=0(Factor left side of equation)

x−2=0 or x+4=0(Set factors equal to 0)

x=2 or x=−4

Check intervals in between critical points. (Test values in the intervals to see if they work.)

x<−4(Works in original inequality)

−4<x<2(Doesn't work in original inequality)

x>2(Works in original inequality)

x<−4 or x>2

Hope this helps! ^-^

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: