Solve the following system of equations:
y = 2x +1
y=-x+ 4

x=?
y=?

x = 1, y = 3

Step-by-step explanation:

Given the 2 equations

y = 2x + 1 → (1)

y = - x + 4 → (2)

Substitute y = 2x + 1 into (2)

2x + 1 = - x + 4 ( add x to both sides )

3x + 1 = 4 ( subtract 1 from both sides )

3x = 3 ( divide both sides by 3 )

x = 1

Substitute x = 1 into (1) and evaluate for y

y = 2(1) + 1 = 2 + 1 = 3

Then solution is x = 1, y = 3

sorry, i don't know i just need points, i'm new here. chao

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0