Given: AACD is isosceles with angle D as the vertex angle. B is the midpoint of AC. AB= x + 5, BC= 2x - 3, and CD = 2x + 6. Find the perimeter of ∆ACD.

Step-by-step explanation:

Given triangle ACD

Perimeter is sum of the side lengths:

AD = CD because D is vertex and the triangle is isosceles

AC = AB + BC because B is midpoint of AC

Then P is:

Find the value of x from the AB = BC:

Then find the value of P:

ok then what happened.