Write y=x^2−6x+4 in vertex form. Then identify the vertex.

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f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

hint: which coefficient is a multiple of 360°?

step-by-step explanation: