Quadratic equations w complex roots
x2 - 6x + 12 = 0

x = 3 ± i

Step-by-step explanation:

Given

x² - 6x + 12 = 0 ( subtract 12 from both sides )

x² - 6x = - 12

Using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 3)x + 9 = - 12 + 9

(x - 3)² = - 3 ( take the square root of both sides )

x - 3 = ± = ± i ( add 3 to both sides )

x = 3 ± i

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

c) yes, because of asa or aas