Does the system shown always, sometimes, or never have a solution when a > b? ax + y = 8
bx + y = 5

always have a solution

Step-by-step explanation:

A linear equation in standard form is given by:

Ax + By = C, where A,B, C are real numbers and A,B is not equal to zero.

Two linear equations with equations Ax + By = C and Dx + Ey = F

Therefore the first equation becomes: (A/B)x + y = C/B and the second equation becomes (D/E)x + y = F/E ]

Both equations are said have a solution if A/B ≠ D/E, they have no solution if A/B = D/E and they have infinite solutions if A/B = D/E, C/B = F/E.

Given that:

when a > b

ax + y = 8

bx + y = 5

Since a ≠ b, but a > b, the system has a solution

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35