Pierre, the mountain climbing ant, moves along the x-axis so that at time t its position is given by x(t) = 2cos(π/2 t^2).

For values of t in the interval [-1,1]
(a)Find an expression for the velocity of the ant at any given time t.
(b) Find an expression for the acceleration at any given time t.
(c)Determine the values of t for which the ant is moving to the right.
Justify your answer.
(d) Determine the values of t for which the ant changes direction.
Justify your answers.

Not sure what the question is but i hope this x = years100 * x

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7  -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so   14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as  -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84  then x = - 0.92 or around -0.9best luck!