Find the Area of the figure below, composed of a parallelogram and one semicircle. Rounded to the nearest tenths place Please help see the picture

Area of the figure= area of the rectangle+ area of the semicircle

=(15×14)+(1/2)π(7)²=210+77=287 square unit

287 square unit is the right answer.

Remember:--- area of the rectangle

=(length×breadth)

and area of the semicircle=π(radius)²/2

this question relies purely on our observation of the graph and a knowledge of the behaviour of a graph of a hyperbola.

now, what we should realise is that there are two asymptotes - one at x = 0 and one at y = 0. what this means is that the graph will gradually approach, but never touch, these two lines. so, as x becomes more positive (ie. 'a very large positive number'), it will get closer to the line y = 0 (ie. the x-axis) - which means that the value of f(x) will gradually become smaller and closer to 0 - but will never reach it.

we can also observe this from the right half of the graph, where the graph gradually lowers closer and closer to the x-axis as x increases. what is important to note however is that it will never actually touch the x-axis (ie. f(x) will not equal 0) since there is an asymptote there. given this, we can see that option d, f(x) is a very small positive number, would be correct.

answer: i think it is (1,-2)