Complete the equation of the line through (-6,5) and (-3,-3) y=

Please help I will give brainiest to the correct answer!

y=-8/3x-11 is the equation of the line and the value of y

Step-by-step explanation:

Use point slope form m = y-y1/x-x1, or y-y1=m(x-x1)

Find the slope from the two points (-6,5) and (-3,-3)

m = y2-y1/x2-x1 = -3-5/-3+6 = -8/3

use one point say (-6,5) that passes through the line and the slope to form the equation y-5=-8/3(x+6) rearrange y= -8/3(x+6)+5

y=-8/3x - 48/3 +5 = -8/3x-16+5 = -8/3x-11

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: