If each side of triangle JKL is 11x larger than triangle FGH, then how many times larger is the area of triangle JKL compared to the area of triangle FGH?
Time Running
Attempt due: Fe
58 Minutes
G
F
H
FH - 10
Area of Triangle FGH = 1

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

4

step-by-step explanation:

im pretty sure it's 4 beacsue 8/2 equals 4

hence, the required result is

step-by-step explanation:

suppose we have two matrices a and b

we will assume the two matrices

we have to compute b-a which means subtracting corresponding elements of a from b.

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