Use the given minimum and maximum data entries, and the number of classes, to find the class width, the lower class limits, and the upper class limits. minimum = 10, maximum = 78, 6 classes
The class width is
Choose the correct lower class limits below.
O A. 10, 22, 34, 46, 58, 70
OB. 22, 33, 46, 58, 70, 81
O c. 10, 21, 34, 45, 57, 70
OD. 21, 33, 46, 57, 69, 81
Choose the correct upper class limits below.
O A. 21, 33, 46, 58, 69, 81
OB. 22, 34, 45, 57, 70, 81
O c. 21, 33, 45, 57, 69, 81
OD. 22, 34, 46, 58, 70, 81

5   1/4   miles per hour

step-by-step explanation:

15   3/4 / 3 = 5   1/4

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1

i those same problems in math and dont know how to do them

third choice down

step-by-step explanation:

the first inequality is based on the number of adults and campers, and the second inequality is based on the cost of feeding both the adult and the camper.

we know that there is room for 525 people max.   it's ok to have less than 525, but it's not ok to have more than 525, so the inequality is less than or equal to.   the number combination of adults (x) and campers (y) cannot exceed this 525 max.   therefore:

x + y ≤ 525

now we talk about cost.   it costs $9 to feed one adult, so depending upon the number of adults you have (x) depends upon how much it will cost to feed that number of adults.   same with the campers, who cost $5 to feed.   the adults can be represented by 9x and the campers can be represented by 5y.   since the budget cannot exceed 1,200, the second inequality is:

9x + 5y ≤ 1200