A bag contains 10 pieces of paper, numbered 1 through 10with a different number on each piece of paper. A second bag contains 8 pieces of paper, numbered 20 through 27with different number on each piece of paper. One piece of paper is drawn random from each bag. What is the expected value of the sum of the numbers on the two selected pieces of paper

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm

X= 2 he can buy 2 packs of cards for $12 and an action figure for $3 so he would spend $15 in total plus the free poster

Ibelieve the answer would be 7, 13, 23