Find the area of the isosceles triangle formed by points of intersection of the parabolas y=-x2+9 and y=2x2+3 and the origin.

10

Step-by-step explanation:

*I’m assuming that you meant y = 2x^2-3 because that is what my RSM problem was and it was exactly the same problem other than that.* First you want to find the points of intersection of the two parabolas. You can choose to graph them or do any other method. Anyways, the points of intersection are: (2,5) and (-2,5). You now want to add (0,0). So obviously (2,5) to (-2,5) is the base and it is 4 units. The height is 0 to 5 which is 5 units. Do (4*5)/2 and you get 10. Hope this helped you with your RSM and let me know if I assumed correctly.

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for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

what statement? is there an image?