If tan=3 by 4 find the value tan+sec

Step-by-step explanation:

As given that ,

tan(Ф)=3/4

Now to find sect(Ф)

we know that,

1+(Ф)=(Ф)

putt values we get ,

(Ф)=1+(3/4)^2

(Ф)=1+9/16

(Ф)=25/16    

sec(Ф)=  +5/4    and sec(Ф)=-5/4      as quadrant is not mentioned so will take both positive and negative values

hence we get ,

tan(Ф)+sec(Ф)=3/4+5/4 = 8/4 = 2

also for sec(Ф)= -5/4

tan(Ф)+sec(Ф)= 3/4-5/4 = -2/4 = -1/2