An isosceles right triangle has a hypotenuse length that can be modeled with the function h(x) = x^2. The combined length of the legs can be modeled with the function L(x) = 2x.
Which function, p(x), can be used to find the perimeter of the triangle?
O p(x) = {V2 + x
O p(x) = x^2 + 2x
O p(x) = x2 + 4x
O p(x) = 2xV2 + 4x

correct answer:

i^31 = -i

i think the answer is fried chicken ; >

step-by-step explanation:

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).