What is an equation of the line that passes through the points (-8, 2) and (-4, -3)?

y = (-6/13)x + (4/13).,

Step-by-step explanation:

the equation of the line is:

y = mx + b, where "m" is the slope and "b" gives the y-intercept

m = (y2 - y1)/(x2 - x1)

m = (-2 - 4)/(5 - (-8))

m = -6/13

y = (-6/13)x + b

the line passes through the point (-8,4) means that for x = -8, y = 4

4 = (-6/13)(-8) + b

b = 4 - (-6/13)(-8)

b = 4/13

the equation of the line that passes through the points (-8,4) and (5,-2) is:

y = (-6/13)x + (4/13).

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

idk

step-by-step explanation: