What are the solutions of (4x+1)^2-9=0

2 solutions: x= -1 x=

Step-by-step explanation:

You could solve this 2 ways, either by factoring or using the quadratic formula.

Factoring:

Use the formula:

(4x+1-3)(3x+1+3)=0

(4x-2)(4x+4)=0

No we can factor out a 2 and a 4:

2(2x-1)4(x+1)=0

Divide both sides by 2x4:

(2x-1)(x+1)=0

Now set both equal to 0:

2x-1=0

x+1=0

x=

x=-1

For quadratic formula:

Use the formula:

First expand the expression:

Divide both sides by 2:

Now we can plug it in:

a=2

b=1

c=-1

Now solve for each solution:

Either way you get the same answer, hope this helps! :)

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

the correct answer is x/3+10≥32

hope this !