Given the function h(x) = -22 – 5x + 13, determine the average rate of change of the function over the interval -8 < x < 2.

Average rate of change = -5.6 for the function h(x) = -22 – 5x + 13,  over the interval -8 < x < 2.

Step-by-step explanation:

Given the function h(x) = -22 -5x + 13, determine the average rate of change

of the function over the interval -8 < x < 2.

The formula used to find average rate of change is:

We have a = -8 and b = 2

We need to find h(b) and h(a)

Put x = 2 in the given equation: h(x) = -22 -5x + 13

h(2) = -22-5(2)+13

h(2) = -22-10+13

h(2) = -22-3

h(2) = -25

So, h(2) = -25

We get: h(b) =h(2) = -25

Put x = -8 in the given equation: h(x) = -22 -5x + 13

h(-8) = -22-5(-8)+13

h(-8) = -22+40+13

h(-8) = 31

So, h(-8) = 31

We get: h(a) =h(-8) = 31

Putting values in formula and finding average rate of change.

So, Average rate of change = -5.6 for the function h(x) = -22 – 5x + 13,  over the interval -8 < x < 2.

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step-by-step explanation:

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graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.