Quadrilaterals WXYZ and W"X"Y"Z"are similar. Identify the type of reflection performed and the scale factor.

A)

To obtain quadrilateral W"X"Y"Z" quadrilateral WXYZ is reflected across

the x-axis and dilated with a scale factor of 3.

B) To obtain quadrilateral W'X'Y"Z" quadrilateral WXYZ is reflected across

the x-axis and dilated with a scale factor of 1/2

c) To obtain quadrilateral W'X'Y"Z" quadrilateral WXYZ is reflected across

the x-axis and dilated with a scale factor of 2.

D) To obtain quadrilateral W X Y Z" quadrilateral WXYZ is reflected across

the x-axis and dilated with a scale factor of 1/3.

B) To obtain quadrilateral W'X'Y"Z" quadrilateral WXYZ is reflected across

the x-axis and dilated with a scale factor of 1/2

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, rotation, translation and dilation.

If a point A(x, y) is reflected across the x axis the new point is at A'(x, -y)

Dilation is the enlargement or reduction in the size of a figure by a scale factor. If a point A(x, y) is dilated by a scale factor of k about the center of origin, the new point is at A'(kx, ky).

The vertex of Quadrilaterals WXYZ is at W(-6, 8), X(-2, 8), Y(-2, 2), Z(-6, 8) while the vertex of Quadrilaterals W"X"Y"Z" is at W"(-3, -4), X"(-2, -4), Y"(-1, -1), Z"(-3, -4)

If quadrilateral WXYZ is reflected across  the x-axis, the new coordinates would be at W'(-6, -), X'(-2, -8), Y'(-2, -2), Z'(-6, -8). If the quadrilateral is then dilated with a scale factor of 1/2, the new point is at W"(-3, -4), X"(-2, -4), Y"(-1, -1), Z"(-3, -4)

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true