The current in one part of a series circuit is 3 – 2j amps. The current in another part of the circuit is 2 + 4j amps. Find the total amps in the circuit. .

The total amps in the circuit described is; 5 +2j

Since current flows in the same direction in a series circuit.

We can evaluate the total current that flows in the circuit as follows;

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5 + 2j Amps

Step-by-step explanation:

current in part one = 3 -2j A

Current in second part = 2 + 4j

Total amps in the circuit = 3 - 2j + 2 + 4j

Collect the like terms

Total amps in the circuit = 3+2-2j+4j

Total amps in the circuit = 5 + 2j

Hence the total amps in the circuit is 5 + 2j Amps

current in the circuit at time t is /, then the power delivered to the resistor is

step-by-step explanation: