In a mid-size company in Philadelphia, the distribution of the number of phone calls answered each day by each of the 12 receptionists is bell-shaped and has a mean of 57 and a standard deviation of 7. Using the empirical (68-95-99.7) rule, what is the approximate percentage of daily phone calls numbering between 50 and 64

Approximately 68% of daily phone calls will be in this interval.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 57

Standard deviation = 7

What is the approximate percentage of daily phone calls numbering between 50 and 64

50 = 57 - 7

So 50 is one standard deviation below the mean

64 = 57 + 7

So 64 is one standard deviation above the mean

By the Empirical Rule, approximately 68% of daily phone calls will be in this interval.

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.