Triangle XYZ at X(–6,1), Y(4,0), Z(1,3) is reflected across the y-axis. What are the new coordinates of the triangle?

X(6, 1), Y(-4, 0), Z(-1, 3)

Step-by-step explanation:

When reflecting an image across the y-axis, (i.e, across a vertical line at the position x = 0), All you need to do is negate the x coordinate of each point, so:

(-6, 1) becomes (6, 1)

(4, 0) becomes (-4, 0)

(1, 3) becomes (-1, 3)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

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step-by-step explanation: