The larger of two numbers is 17 more than twice the smaller. When the larger number is divided by the smaller, the quotient is 3 and the remainder is 6. Find the two numbers

The numbers described here are 39 and 11.

Step-by-step explanation:

Let's call the numbers a and b, a being the larger. We're told two things:

The larger of the two numbers is 17 more than twice the smaller.

Which we can express as:

a = 2b + 17

When the larger number is divided by the smaller, the quotient is 3 and the remainder is 6

And that can be expressed as:

a = 3b + 6

We can now take those two expressions and, noting that they both define a, we can say that they are equivalent, and solve for b:

2b + 17 = 3b + 6

3b - 2b = 17 - 6

b = 11

With b found, we can now take either of the first expressions, and solve for a:

a = 2b + 17

a = 2(11) + 17

a = 22 + 17

a = 39

Now we can check whether that is correct by plugging it into the other expression and seeing if b still comes to 11:

a = 3b + 6

39 = 3b + 6

3b = 33

b = 11

So we know that the answer is correct.

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: