What is the solution to the system of equations below? y = negative 3 x minus 9 and y = one-third x minus 39
(9, –36)
(9, 0)
(–9, 18)
(–9, –42)

A. (9, –36)

Step-by-step explanation:

The equations are given as:

i) y = -3x - 9

ii) y= 1/3 x - 39

Use equation i) in equation ii)

-3x - 9 = 1/3 x - 39 multiply each term by 3 to remove the fraction

-9 x - 27 = x - 117

collect like terms

-9 x- x = -117 + 27

-10 x = -90

10x = 90

x = 90 / 10

x = 9 iii

Use equation iii  in i

y = -3x - 9  

y = -3 * 9 - 9

y= -27 - 9

y= -36

Hence,

x = 9  , y = -36

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.