Particle x moves along the positive x-axis so that it's position at time t is less than equal to 0 is given by x(t)= 5t^3 - 9t^2 + 7. Is particle x moving toward the right at time t=1?

Step-by-step explanation:

Given the position of the particle expressed using the expression;

x(t)= 5t^3 - 9t^2 + 7 where;

x moves along the positive x-axis

when t = 1

x(1) = 5(1)^3 - 9(1)^2 + 7

x(1) = 5 - 9 + 7

x(1) = -4 + 7

x(1) = 3

Since the position of the particle is positive at t = 1, hence the particle is moving towards the right at time t = 1

there would be 365 different 4 digit numbers

step-by-step explanation:

i belive that it is 365 because i asked google

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: