A 41-inch piece of steel is cut into three pieces so that the second piece is twice as long as the first piece, and the third piece is one inch more than five times the length of the first piece. Find the lengths of the pieces.

Length of first piece = 5 inches

Length of second piece = 10 inches

Length of third piece = 26 inches

Step-by-step explanation:

Given that:

Length of piece of steel = 41 inch

Let,

x be the length of first piece

y be the length of second piece

z be the length of third piece

According to given statement;

x+y+z = 41          Eqn 1

y = 2x                Eqn 2

z = 5x+1            Eqn 3

Putting value of y and z from Eqn 2 and 3 in Eqn 1

Dividing both sides by 8

Putting x=5 in Eqn 2 and 3

y = 2(5) = 10

z = 5(5) + 1 = 25+1 = 26

Hence,

Length of first piece = 5 inches

Length of second piece = 10 inches

Length of third piece = 26 inches

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