point q is located at (18, 5). The x-coordinate of point r id half as much as the x-coordinate of point Q The y-coordinate of point r is 3 more than the y-coordinate of point q

R (27, 8)

Step-by-step explanation:

The coordinate plane is a two-dimensional plane consisting of the y axis (vertical line) and x-axis (horizontal line). The origin is known as the zero point (reference point) is the intersection of the x axis and y axis.

A point on the coordinate plane is represented by (x, y) where x is the x coordinate and y the y coordinate.

Given point Q = (18, 5), the x coordinate is 18 and the y coordinate is 5.

Let the location of point R = (a, b)

a = x-coordinate of point Q + 1/2 of x-coordinate of point Q = 18 + (1/2)*18 = 27

b = y-coordinate of point Q + 3 = 5 + 3 = 8

Therefore R = (27, 8)

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

i think the answer is d im not sure