A lake near the Arctic Circle is covered by a 3 meter thick sheet of ice during the cold winter months. When spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a constant rate. After four weeks, she is only 1.6 m thick. Pls hurry!

Complete question :

A lake near the Arctic Circle is covered by a 3 meter thick sheet of ice during the cold winter months. When spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a constant rate. After four weeks, she is only 1.6 m thick. Let S(t) denote the ice sheet's thickness S (measured in meters) as a function of time t (measured in weeks). Write the function's formula

S(t) = 3 - 0.3t

Step-by-step explanation:

Given that:

Initial thickness = 3m

Assume the rate of decrease is constant

Thickness after 4 weeks = 1.6 m

To obtain a function for the scenario described above :

We can observe that the function is a linear function, given that rate of decrease per week is constant :

To obtain the rate of decrease :

Change after 4 weeks :

(Initial thickness - thickness after 4 weeks) / number of weeks

(3m - 1.6m) / 4

= 1.2m / 4

= 0.3 m per week

General form of a linear function :

y = mx + c

m = rate of change per unit

Hence, our function becomes ;

S(t) = 3 - 0.3t

what are the options? ?

step-by-step explanation:

answer: sine

step-by-step explanation: