I need help anyone please ?

7.

x=16

DE = 167

EF=13

DFG = 347

8.

x=11

MN = 65

NP = 115

NQP =245

Step-by-step explanation:

Part1 Alright so arc length EF and FG have supplementary angles meaning that the two arc lengths added together will equal 180. So we setup the equation

12x-25+x-3=180 then we solve

step 1 combine like terms

13x-28=180

step 2 add 28 to each side

13x=208

step 3 divide each side by 13

x=16

Then we plug in to find arc lengths EF and FG and get that FG =167 and EF = 13

Because DE is vertical from FG they have the same arc length so DE = 167

For the last arc length DFG we just subtract arc length DG from 360 to get 347

Part 2 arc MN and QP are vertical from each other so they have the same arc length so we setup the equation 10x-45 = 6x-1 then we solve for x

step 1 subtract 6x from each side

4x-45=-1

step 2 add 45 to each side

4x=44

step 3 divide each side by 4x to get x=11 then we plug in for arc length MN to get mn = 65

Side Mn and NP are supplementary (the angles added together = 180.) so we subtract 65 from 180 to get 115 so NP = 115

damm bro the struggle

step-by-step explanation: