Duplicate. with attachments
find the surface area of the pyramid shown to the nearest whole number.
7.
72 ft2
128 ft2
56 ft2
22 ft2

8.
1,300 m2
390 m2
650 m2
628 m2

9. find the slant height x of the pyramid shown, to the nearest tenth.
4.35 mm
9.2 mm
6.9 mm
3.6 mm

10. find the surface area of the cone to the nearest tenth.
132 cm2
138 cm2
490.1 cm2
867.1 cm2

11. find the slant height of the cone to the nearest whole number.
20 m
22 m
21 m
19 m
"

your answer is d 2,500

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.