Three numbers are in the ratio 3:4:5. If the smallest is 2x−7, what is the product of the two other numbers?

The product is;

(80x^2-560x+ 980)/9

Step-by-step explanation:

Here, we want to get the product of the two smaller numbers

let the mid number be y

3/4 = 2x-7/y

3y = 8x-28

y = (8x-28)/3

Let the biggest be z

3/5 = 2x-7/z

3z = 10x -35

z = (10x-35)/3

The product of the two other numbers is thus;

(10x-35)/3 * (8x-28)/3

= (10x-35)(8x-28)/9

(80x^2-280x - 280x + 980)9

= (80x^2 - 560x + 980)/9

sum= when you add is how much the whole amount is

distance= when you use angles and it means how far it goes

step-by-step explanation:

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1