What do I do to get this answer? Could you provide me a step by step to understand where you get the numbers from? Thank you, will be using them as notes for the rest.

$546.25 is the total pay for that week

Step-by-step explanation:

Allen makes $11.50 per hour. That means that if he works 40 hours per week, he will make 460$.

$11.50 * 40 hours = $460 per week

Overtime is any number of hours he works over 40 hours per week. Allen makes 50% more for every hour of overtime. Instead of making 11.50, he will be making $17.25.

$11.50 * 1.5 = $17.25 per hour of overtime

To solve the problem:

1. How many hours were worked total on that particular week?

2. How many hours were normal time, how many were overtime?

3. Multiply normal time hours by $11.50, overtime hours by $17.25.

4. Add them together for the total compensation

Solution:

The week of 5/17, Allen worked 45 hours total. This is 40 hours of normal time, 5 hours of overtime.

40 hours * $11.50 = $460.00

5 OT hours * $17.25 = $86.25

$460.00 + $86.25 = $546.25 is the total amount earned that week.

i think it's eleven too, don't woosh me here, but according to the "experts" it's 2.

the proof starts from the peano postulates, which define the natural

numbers n. n is the smallest set satisfying these postulates:

  p1.   1 is in n.

  p2.   if x is in n, then its "successor" x' is in n.

  p3.   there is no x such that x' = 1.

  p4.   if x isn't 1, then there is a y in n such that y' = x.

  p5.   if s is a subset of n, 1 is in s, and the implication

      (x in s => x' in s) holds, then s = n.

then you have to define addition recursively:

  def: let a and b be in n. if b = 1, then define a + b = a'

      (using p1 and p2). if b isn't 1, then let c' = b, with c in n

      (using p4), and define a + b = (a + c)'.

then you have to define 2:

  def:   2 = 1'

2 is in n by p1, p2, and the definition of 2.

theorem:   1 + 1 = 2

proof: use the first part of the definition of + with a = b = 1.

      then 1 + 1 = 1' = 2   q.e.d.

note: there is an alternate formulation of the peano postulates which

replaces 1 with 0 in p1, p3, p4, and p5. then you have to change the

definition of addition to this:

  def: let a and b be in n. if b = 0, then define a + b = a.

      if b isn't 0, then let c' = b, with c in n, and define

      a + b = (a + c)'.

you also have to define 1 = 0', and 2 = 1'. then the proof of the

theorem above is a little different:

proof: use the second part of the definition of + first:

      1 + 1 = (1 + 0)'

      now use the first part of the definition of + on the sum in

      parentheses:   1 + 1 = (1)' = 1' = 2   q.e.d.

b is the right answer