A ball is thrown from an initial height of 3 meters with an initial upward velocity of 9 m/s. The ball's height h (in meters) after seconds is given by the following
h= 3 +91-512
Find all values of 1 for which the ball's height is 6 meters.
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)

12*c

step-by-step explanation:

a. is correct

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15